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(D) The electrical conductivity of coordination compounds depends on the number of ions produced in the solution. $1$. $[Co(NH_3)_6]Cl_3$ dissociates

Vedclass · Accepted Answer

$[Co(NH_3)_6]Cl_3 > [CoCl(NH_3)_5]Cl_2 > [CoCl_2(NH_3)_4]Cl > [CoCl_3(NH_3)_3]$ (Order of electrical conductivity)

Vedclass · Answer

(D) The electrical conductivity of coordination compounds depends on the number of ions produced in the solution. $1$. $[Co(NH_3)_6]Cl_3$ dissociates into $4$ ions $([Co(NH_3)_6]^{3+} + 3Cl^-)$. $2$. $[CoCl(NH_3)_5]Cl_2$ dissociates into $3$ ions $([CoCl(NH_3)_5]^{2+} + 2Cl^-)$. $3$. $[CoCl_2(NH_3)_4]Cl$ dissociates into $2$ ions $([CoCl_2(NH_3)_4]^+ + Cl^-)$. $4$. $[CoCl_3(NH_3)_3]$ is a non-electrolyte and does not dissociate into ions. Therefore,the correct order of electrical conductivity is $[Co(NH_3)_6]Cl_3 > [CoCl(NH_3)_5]Cl_2 > [CoCl_2(NH_3)_4]Cl > [CoCl_3(NH_3)_3]$.

Select the option containing the correct order of the given parameter.

Similar Questions

The brown ring test for $NO_2^-$ and $NO_3^-$ ions is due to the formation of which of the following complex ions?

With which of the following will ammonia $NOT$ form a complex compound?

Which of the following ions forms a complex with a coordination number of $2$ in the presence of excess $CN^{-}$?

Which complex is most stable? Where $k_d =$ Dissociation constant.

For the complex $ML_2$,the stepwise formation constants for the reactions:
$M + L \rightleftharpoons ML$
$ML + L \rightleftharpoons ML_2$
are $4$ and $3$ respectively. Hence,the overall stability constant for the reaction:
$M + 2L \rightleftharpoons ML_2$
is:

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